16k^2-36k-36=0

Solution for 16k^2-36k-36=0 equation:

16k^2-36k-36=0

a = 16; b = -36; c = -36;
Δ = b2-4ac
Δ = -362-4·16·(-36)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-60}{2*16}=\frac{-24}{32}
=-3/4
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+60}{2*16}=\frac{96}{32}
=3
$